[xsl] Re: detecting attribute node type

[Dimitre Novatchev <dnovatchev at yahoo dot com>]

Oleg Tkachenko wrote:

> Is there an efficient way to detect by XPath expression (not by a pattern) that 
> current node is an attribute node ?
> I know solution like count(../@* | .)=count(../*), but I believe it's too 
> unefficient for this simple task.

Hi Oleg,

Most probably you ment not:

> count(../@* | .)=count(../*)

but:

count(../@* | .)=count(../@*)


There's another expression that evaluates to true only for an attribute node. The
following will perform ***considerably faster*** with MSXML3 because of their very
efficient implementation of the generate-id() function:

generate-id() = generate-id(../@*[name()=name(current())])

Cheers,
Dimitre Novatchev.

---
Oleg Tkachenko
Multiconn International



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