RE: [xsl] Position of a result tree fragment

["Chris Bayes" <Chris at Bayes dot co dot uk>]

Larry,
Add it's original position to the rtf when you make it.

Ciao Chris

XML/XSL Portal 
http://www.bayes.co.uk/xml


>-----Original Message-----
>From: owner-xsl-list@lists.mulberrytech.com
>[mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Laurence O
>Garfield
>Sent: 19 July 2001 00:08
>To: xsl-list@lists.mulberrytech.com
>Subject: [xsl] Position of a result tree fragment
>
>
>If I am passing a result tree fragment from one template to another using
>a variable, is there any way to determine what the fragment's position
>within its parent was originally?  According to the XSLT spec I can't use
>/, //, or [] on result tree fragments, so I can't use [position()].  Is
>there some other way, or do I have to pass the position of the node
>through as a second variable as well?
>
>--Larry Garfield
>lgarfiel@students.depaul.edu
>
>DePaul Linux Users Group Secretary
>
>-- "If at first you don't succeed, skydiving isn't for you." :-)
>
>
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>

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