RE: [xsl] How to sort a nodeset referenced by a variable?

[Kumar dot Shailendra at morganstanley dot com]

Hi Mike,
Thanks for the response I got it working. 

I changed the sort key from 
<xsl:sort select="$fileterNode/secondElement"> 
to
<xsl:sort select="./secondelement" />

It started working. I think now I understand your point.

regards,
Shailendra

On Wed, 4 Jul 2001, Michael
Kay
wrote:

> > I am doing something like this
> >
> > <xsl:variable name="filterdNode" select="//*" />
> >
> > <xsl:variable name="sortedList">
> > <xsl:for-each select="$filterNode/someElement">
> >  <xsl:sort select="$fileterNode/secondElement">
> 
> The value of your sort key will be the same for every node in the
> collection. It's meaningless to use a sort key whose value doesn't depend on
> the context node.
> 
> Mike Kay
> Software AG
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list