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Re: Why is my xsl:param empty? (passed with xsl_with-param)
- To: RdVries at PCL-HaGe dot nl
- Subject: [xsl] Re: Why is my xsl:param empty? (passed with xsl_with-param)
- From: Dimitre Novatchev <dnovatchev at yahoo dot com>
- Date: Fri, 15 Jun 2001 02:44:14 -0700 (PDT)
- Cc: xsl-list at lists dot mulberrytech dot com
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi Rene,
In your template:
<xsl:template match="/">
<xsl:apply-templates>
<xsl:with-param name="trythis" select="8"/>
</xsl:apply-templates>
</xsl:template>
you are applying the templates to all children (and there's always one -- the top
element) of the root node.
It happens to be a node named "root", for which you haven't provided a matching
template.
Then the XSLT default processing is carried on this node and as part of it a
xsl:apply-templates (without parameters!!!) is initiated for the children of "root".
But notice -- the default processing doesn't know about any parameters that need be
passed -- therefore your template matching "x" is applied without any parameters
being provided.
This explains the output you received.
Cheers,
Dimitre Novatchev.
Rene de Vries wrote:
I'm playing around with xsl:with-param and xsl:param, but I cant get my param
passed. What do I do wrong?
I expect:
$trythis: 8
$trythis: 8
but I get
$trythis:
$trythis:
xml:
<root>
<x>bla</x>
<x>blabla</x>
</root>
xsl:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:apply-templates>
<xsl:with-param name="trythis" select="8"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="x">
<xsl:param name="trythis"/>
<p>
$trythis: <xsl:value-of select="$trythis"/>
</p>
</xsl:template>
</xsl:stylesheet>
Greetings Rene
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