Re: [xsl] Proper syntax for counting all prior nodes in XPath?

[Johannes Döbler <jd at aztecrider dot com>]

Try the XPath expression 'count(preceding::* | ancestor::*)' to count all 
the element nodes prior to the context node.

Johannes

At 11:16 11.06.01 -0600, you wrote:
>Hi,
>
>With an XML document like this:
><DOC>
>         <CHAPTER>
>                 <SECTION>
>                         <PAGE>
>                                 <LINE>Test</LINE>
>                                 <LINE>Test 2</LINE>
>                         </PAGE>
>                 </SECTION>
>                 <SECTION>
>                         <PAGE>
>                                 <LINE>Test 3</LINE>
>                         </PAGE>
>                 </SECTION>
>         </CHAPTER>
></DOC>
>
>How can my XSL count all the preceding nodes?  For example, when my template
>is processing the <LINE>Test 3</LINE>, I want to count all nodes before it,
>which would be 2 <LINE>s, 2 <PAGE>s, 2 <SECTION>s, 1 <CHAPTER>, and 1 <DOC>.
>Does this make sense?
>
>It would be something like <xsl:number level="any"
>count="DOC|CHAPTER|SECTION|PAGE|LINE"/>, except I want to use the count in
>an <xsl:if />, not just display it.  I have tried using <xsl:if
>test="count(something)">, but I do not know what the proper "something" is.
>Any suggestions?
>
>Thanks
>Jason


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