RE: [xsl] Distinct items?

[eric at perceive dot net (Eric Vitiello)]

OK, I just realized another step I'd like to do.  My XML is:


 <projects>
 	<item>
 		<year>1998</year>
		<title>This is the first item</title>
 	</item>
 	<item>
 		<year>2000</year>
		<title>This is the second item</title>
 	</item>
 	<item>
 		<year>1999</year>
		<title>This is the third item</title>
 	</item>
 	<item>
 		<year>2000</year>
		<title>This is the fourth item</title>
 	</item>
 	<item>
 		<year>1998</year>
		<title>This is the fifth item</title>
 	</item>
</projects>


with the following XSLT:

<xsl:for-each  select='//item[not(year = preceding-sibling::item/year)]'>
	<xsl:sort select="projects/item/year" data-type="number" order="descending"/>
	<xsl:sort select="projects/item/month" data-type="number" order="descending"/>
	<xsl:sort select="projects/item/day" data-type="number" order="descending"/>
		<xsl:value-of select="year"/>  
</xsl:for-each>

I get:

1998 1999 2000


I would like then to be able to list the data such as:

1998
  * This is the first item
  * This is the fifth item

1999
  * This is the third item

2000
  * This is the second item
  * This is the fourth item


Got code for that?

I'm just starting with XSLT, and the syntax of selects, etc keeps throwing me off.

--Eric

> Hello
> You can use this:
>  select='//item[not(year = preceding-sibling::item/year)]'>
> 
> I hope that helps
> 
> Edmund
> 
> -----Original Message-----
> From: eric@perceive.net [mailto:eric@perceive.net]
> 
> I would like to retrieve a list of items such as:
> 
> 1998 1999 2000
> 
> from the following XML:
> 
> <projects>
> 	<item>
> 		<year>1998</year>
> 	</item>
> 	<item>
> 		<year>1998</year>
> 	</item>
> 	<item>
> 		<year>1999</year>
> 	</item>
> 	<item>
> 		<year>2000</year>
> 	</item>
> 	<item>
> 		<year>2000</year>
> 	</item>
> </projects>
> 
> 
> 	
>  
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list