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replace each same character by another one (or more)
- To: "'XSL-List at lists dot mulberrytech dot com'" <XSL-List at lists dot mulberrytech dot com>
- Subject: [xsl] replace each same character by another one (or more)
- From: Kristof Bernaert <kbernaert at 1eEurope dot be>
- Date: Tue, 27 Mar 2001 11:29:16 +0200
- Reply-To: xsl-list at lists dot mulberrytech dot com
where a quote-sign ( ' ) is used in xml-doc, it has to be replaced by slash
+ quote-sign ( /' )
how to process a whole document at once ?
i tried already like this:
<xsl:template match="Body"><xsl:value-of select=" ....
but this don't result in a node, just the value of, with the result when the
element Body is called, only the value is given, thus, without the lay-out
defined in 'template-match' for elements included in the Body element
ps: the only way i can call the node Body is like this, <xsl:apply-templates
select="Information/Body"/> (within javascript)
some nice brain with solution ? :-)
thx
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