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Re: Testing position of parent



> I believe they will return the same result, but I'm
> wondering if there's any tradeoffs to each approach.
> 
> You said:      test="parent::lg[not(preceding-sibling::*)]"
> David C. said: test="not(parent::lg[preceding-sibling::*])"

they are not actually equivalent, which was what I was alluding to when I
said 


me> (exactly what you want depending on whether you also want to test
me> whether the parent is lg.

Mike's test is true if

the parent node is an lg and it is the first element amongst its
siblings.

My test is true if it isn't the case that the parent is an lg and has
preceding sibling elements.

In particular if the parent isn't lg then my test will be true
but Mike's will be false.

But it may be that in the context you know its an lg anyway...

David


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