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Nodeset displayed as <ul>-list
- To: "'xsl-list at mulberrytech dot com'" <xsl-list at mulberrytech dot com>
- Subject: Nodeset displayed as <ul>-list
- From: Conny Kreyßel <Conny dot Kreyssel at inter-forum dot de>
- Date: Tue, 1 Aug 2000 12:43:27 +0200
- Reply-To: xsl-list at mulberrytech dot com
I would like build my website with XML/XSL. The navigation should
automaticly generated with XSL. So I have written the structure from my
website in XML. A example:
<tree>
<nav id="123" title="Page 1"/>
<nav id="124" title="Page 2">
<nav group="section 1"/>
<nav id="125" title="Page 4">
<nav id="126" title="Page 5"/>
<nav id="127" title="Page 6"/>
<nav id="128" title="Page 7"/>
</nav>
<nav id="129" title="Page 8">
<nav id="130" title="Page 9"/>
</nav>
.
.
<nav group="section 2"/>
<nav id="131" title="Page 11"/>
.
.
</nav>
</tree>
Ok now I would describe you my intention. The "id"-attribute its only for
selection. The "title"-attribute should be the text whos displayed in the
navigation-list. The "group"-attribute is only used as a seperator.
Now i would select a node-set as follows:
<xsl:for-each select="id($navid)/ancestor::* |
id($navid)/ancestor::*/child::*">
<xsl:if test="count(ancestor::*) >= $sd and count(ancestor::*)
<= $ed">
<xsl:if test="boolean(@title)">
<xsl:value-of select="@title"/>
</xsl:if>
<xsl:if test="boolean(@group)">
<b><xsl:value-of select="@group"/></b>
</xsl:if>
<br/>
</xsl:if>
</xsl:for-each>
$navid is the id which tag I select - $sd is the start-depth and $ed is the
end-depth of the node-set.
Now my problem: In this case all "title" will right displayed and in the
right order. But I would like also display the structure of the node-set in
a list(<ul>, <li>). How must I redesign the code to display the structure
right?
I have tried to create the list like the example in "XSLT Programmers
Reference" (Page 302) but it will not worked in cocoon. The <xsl:text
disable-output-escaping="yes"> dont work.
Can you please help me?
- Conny -
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