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Problem using XSL
- To: <xsl-list at mulberrytech dot com>
- Subject: Problem using XSL
- From: "Stéphane Mamdy" <smamdy at agrifirst dot com>
- Date: Fri, 9 Jun 2000 16:56:52 +0200
- Reply-To: xsl-list at mulberrytech dot com
Hi,
I amquite new in using XML.
I have done an XML doc like this:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<?xml:stylesheet type="text/xsl" href="liste_cron1.xsl"?>
<LPlan>
<Plan>
<MOTEUR ID_MOTEUR="Agritest">Agritest</MOTEUR>
<SITE ID_SITE="15">agrifirst</SITE>
</Plan>
<Plan>
<MOTEUR ID_MOTEUR="Agritest - Altavista">Agritest - Altavista</MOTEUR>
<SITE ID_SITE="15">agrifirst</SITE>
</Plan>
</LPlan>
I have this XSL document:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"
xmlns="http://www.w3.org/TR/REC-html4.0" result-ns="">
<xsl:template match="/">
<html xmlns="">
<head>
<link REL="stylesheet" TYPE="text/css" HREF="cell.css"/>
</head>
<body>
<xsl:apply-templates select="LPlan"/>
</body>
</html>
</xsl:template>
<xsl:template match="LPlan">
<xsl:for-each select="Plan" order-by="SITE">
num de ligne <xsl:value-of select="position()" />
<p/>
<xsl:value-of select="MOTEUR"/>
<xsl:value-of select="SITE"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
This line :
num de ligne <xsl:value-of select="position()" />
doesnt work with IE5 ...
Why ? I don't find any information about it....
Perhaps do i forget something ?
Thanks for you help.
Stéphane Mamdy.
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