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Re: [PATCH] remove one nested function from nptl/allocatestack.c


Bool is easy, done. (I did not realize that this code uses bool. Great!)
Comments are harder -- I do not feel comfortable re-commenting someone
else's code.
Do you have a suggestion?

On Wed, Jun 4, 2014 at 9:16 PM, Roland McGrath <roland@hack.frob.com> wrote:
> That is fine, though it wouldn't hurt to improve the commentary and use
> bool while you're there.
diff --git a/nptl/allocatestack.c b/nptl/allocatestack.c
index 1e22f7d..359c444 100644
--- a/nptl/allocatestack.c
+++ b/nptl/allocatestack.c
@@ -809,6 +809,24 @@ __make_stacks_executable (void **stack_endp)
   return err;
 }
 
+/* We always add at the beginning of the list.  So in this
+   case we only need to check the beginning of these lists.  */
+static bool
+check_list (list_t *l, list_t *elem)
+{
+  if (l->next->prev != l)
+    {
+      assert (l->next->prev == elem);
+
+      elem->next = l->next;
+      elem->prev = l;
+      l->next = elem;
+
+      return true;
+    }
+
+  return false;
+}
 
 /* In case of a fork() call the memory allocation in the child will be
    the same but only one thread is running.  All stacks except that of
@@ -830,26 +848,8 @@ __reclaim_stacks (void)
 
       if (add_p)
 	{
-	  /* We always add at the beginning of the list.  So in this
-	     case we only need to check the beginning of these lists.  */
-	  int check_list (list_t *l)
-	  {
-	    if (l->next->prev != l)
-	      {
-		assert (l->next->prev == elem);
-
-		elem->next = l->next;
-		elem->prev = l;
-		l->next = elem;
-
-		return 1;
-	      }
-
-	    return 0;
-	  }
-
-	  if (check_list (&stack_used) == 0)
-	    (void) check_list (&stack_cache);
+	  if (!check_list (&stack_used, elem))
+	    (void) check_list (&stack_cache, elem);
 	}
       else
 	{

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