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How to set procedure name in macros
- From: Duncan Mak <duncanmak at gmail dot com>
- To: kawa mailing list <kawa at sourceware dot org>
- Date: Sun, 1 Jan 2017 17:59:18 -0500
- Subject: How to set procedure name in macros
- Authentication-results: sourceware.org; auth=none
Hello all,
Happy new year!
In my DEFINE-FOO macro and I noticed that I can't control the name of
the lambda in the syntax expansion.
Here's a test case -
(define-syntax define-a
(lambda (stx)
(syntax-case stx ()
((_ name) #`(define name (lambda () #f))))))
(define-syntax define-bar
(lambda (stx)
(syntax-case stx ()
((_ name) #`(define name (lambda () name: 'bar #f))))))
(define-syntax define-c
(lambda (stx)
(syntax-case stx ()
((_ name) #`(define name (letrec ((foo (lambda () name: name
#f))) foo))))))
(define-syntax define-d
(lambda (stx)
(syntax-case stx ()
((_ name) #`(define name (letrec ((foo (lambda () #f)))
(set-procedure-property! foo 'name name) foo))))))
(define-a a)
(format #t "Should say a: ~A~%" (procedure-property a 'name))
(define-bar b)
(format #t "Should say bar: ~A~%" (procedure-property b 'name))
(define-c c)
(format #t "Should say c: ~A~%" (procedure-property c 'name))
(define-d d)
(format #t "Should say d: ~A~%" (procedure-property d 'name))
The output looks like this:
Should say a: a
Should say bar: b
Should say c: foo
Should say d: foo
I'm particularly interested in the C or D cases.
Thanks!
--
Duncan.