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[Bug stdio/12836] fmemopen(buf,size,"w+b") isn't binary
- From: "allachan at au1 dot ibm.com" <sourceware-bugzilla at sourceware dot org>
- To: glibc-bugs at sourceware dot org
- Date: Thu, 30 Jan 2014 03:50:54 +0000
- Subject: [Bug stdio/12836] fmemopen(buf,size,"w+b") isn't binary
- Auto-submitted: auto-generated
- References: <bug-12836-131 at http dot sourceware dot org/bugzilla/>
https://sourceware.org/bugzilla/show_bug.cgi?id=12836
paxdiablo <allachan at au1 dot ibm.com> changed:
What |Removed |Added
----------------------------------------------------------------------------
CC| |allachan at au1 dot ibm.com
--- Comment #5 from paxdiablo <allachan at au1 dot ibm.com> ---
The POSIX standard calls for fmemopen() to accept all mode strings as allowed
in fopen() but notes that use of "b" results in implementation-defined
behaviour.
So, technically, I think an implementation _could_ treat w+b and wb+ as
different if it so desired but it would have to document that.
Of course, it would probably be easier to fix the code to make them identical
:-)
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