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[Bug libc/3432] New: memmove() does not conform with the C99 standard.
- From: "yuvalfl at gmail dot com" <sourceware-bugzilla at sourceware dot org>
- To: glibc-bugs at sources dot redhat dot com
- Date: 29 Oct 2006 09:36:34 -0000
- Subject: [Bug libc/3432] New: memmove() does not conform with the C99 standard.
- Reply-to: sourceware-bugzilla at sourceware dot org
By reviewing the glibc sources it turns out that memmove() only does word copy.
Thus, the function will not work correctly when |dst-src|<|word|.
The C99 standard (section 7.21.2.2 "The memmove function") mandates:
---
#include <string.h>
void *memmove(void *s1, const void *s2, size_t n);
The memmove function copies n characters from the object pointed to by
s2 into the object pointed to by s1. Copying takes place as if the n
characters from the object pointed to by s2 are first copied into a
temporary array of n characters that does not overlap the objects
pointed to by s1 and s2, and then the n characters from the temporary
array are copied into the object pointed to by s1.
---
--
Summary: memmove() does not conform with the C99 standard.
Product: glibc
Version: unspecified
Status: NEW
Severity: minor
Priority: P2
Component: libc
AssignedTo: drepper at redhat dot com
ReportedBy: yuvalfl at gmail dot com
CC: glibc-bugs at sources dot redhat dot com
http://sourceware.org/bugzilla/show_bug.cgi?id=3432
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