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RE: document() and xpath
- From: "Michael Kay" <michael dot h dot kay at ntlworld dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Mon, 29 Apr 2002 20:09:18 +0100
- Subject: RE: [xsl] document() and xpath
- Reply-to: xsl-list at lists dot mulberrytech dot com
Declare a global variable
<xsl:variable name="root" select="/"/>
and when you want to refer to the original document, write
select="$root/x/y/z".
Michael Kay
Software AG
home: Michael.H.Kay@ntlworld.com
work: Michael.Kay@softwareag.com
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Meltem
> Kogelbauer
> Sent: 29 April 2002 19:39
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] document() and xpath
>
>
>
> Hi All,
>
> here is the simplified version of code;
> 1st XML that is generated on-the-fly
> <page>
> <form>
> <name/>
> <id/>
> </form>
> ...
> </page>
>
> 2nd XML that is a flat file, xml.xml
> <menu>
> <name/>
> <name/>
> <name/>
> </menu>
>
> In the XSL
>
> <for-each select="document('xml.xml')/menu/name">
> <value-of select="text()"/>
> <apply-templates select="/page/form" />
> </for-each>
>
>
> My problem is with the xpath (I think) in <apply-templates>
> element. When
> looping in the external XML, how can I write the XPath to the current
> document? Is this possible?
>
> cheers
>
> Meltem
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
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