Re: [xsl] incrementing a counter in XSL

[Wendell Piez <wapiez at mulberrytech dot com>]

Becky,

Greg's solution is the best (cleanest and simplest). But if you can't use 
it, e.g. because you have to do other things with other elements inside 
your for-each but not inside your test, you can adapt xsl:number to do what 
you need:

<xsl:for-each select="Contract/TermRdr">
   <xsl:if test="StatusCd='A' or StatusCd='F'">
     <SequenceNum fieldType="Short" elementType="field">
       <xsl:number count="TermRdr[StatusCd='A' or StatusCd='F']"/>
     </SequenceNum>
             ....
   </xsl:if>
</xsl:for-each>

You don't need to give xsl:number an explicit value here; its whole job is 
to number things.

Cheers,
Wendell

At 02:05 PM 4/18/2002, you wrote:

>---------------------- Forwarded by Becky Foley/IIG/Prudential on
>04/18/2002 02:05 PM ---------------------------
>Becky Foley    Thursday April 18, 2002 12:13 PM
>       (973) 802-6567
>To:    XSL-List@lists.mulberrytech.com
>cc:
>Subject:    incrementing a counter in XSL
>
>I am selecting some nodes from an XML doc with an if statment in a for-each
>loop.  Out of the set of nodes I am looping through, I am only selecting
>some in the if statment.  Each of these nodes that is selected by the if
>statement needs a sequence number.  Originally I was using :
>      <xsl:for-each select="Contract/TermRdr">
>             <xsl:if test="StatusCd='A' or StatusCd='F'">
>                   <SequenceNum fieldType="Short" elementType
>="field"><xsl:number value ="position()"/></SequenceNum>
>             ....
>       </xsl:if>
>    </xsl:for-each>
>
>but I realized I was getting the position from the source xml.  So if the
>if statement selected 2 of the 5 nodes, they could end up with sequence
>numbers 2 and 4 as opposed to the 1 and 2 I am looking for.


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