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Re: arguments for xsl:call-template
- From: "Thomas B. Passin" <tpassin at mitretek dot org>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Fri, 7 Dec 2001 10:13:00 -0500
- Subject: Re: [xsl] arguments for xsl:call-template
- References: <004d01c17f46$0369ace0$c4c909c0@COHANA>
- Reply-to: xsl-list at lists dot mulberrytech dot com
[Charly]
> Does anyone of you has any idea how to call a template and passing with a
> node as argument.
> I'm trying the following .
>
> <xsl:template name="histogram">
> <xsl:param name="path" />
> <xsl:for-each select="$path">
> <xsl:value-of select="@value"/>
> </xsl:for-each>
> </xsl:template>
>
> <xsl:call-template name="histogram">
> <xsl:with-param name="path" select="'/report/histo/bar'" />
> </xsl:call-template>
>
Just change to one set of quotes in the select attribute and the select will
return a set of nodes, just what you asked for. In other words, your
attribute value as you wrote it is a string (because of the extra set of
quotes), and you want it to be a node-set.
Tom P
> my XML looks like .
> <report>
> <histo>
> <bar value="20" />
> <bar value="30" />
> <bar value="40" />
> <bar value="50" />
> </histo>
>
> </report>
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