RE: question with using Muenchian/xsl:key (Re: sort/group/count probl em)

[Xiaocun Xu <XXu at CommercialWare dot com>]

Thanks for the suggestion, but this did not seems to work.
When I changed to use="concat(generate-id(..),@itemid)", the group by
@itemid was not built.

Xiaocun

-----Original Message-----
From: David Carlisle
To: xsl-list@mulberrytech.com
Sent: 11/11/00 3:30 PM
Subject: Re: question with using Muenchian/xsl:key (Re: sort/group/count
probl em)

> 
> key('items-by-itemid', @itemid) returns all items with the same
@itemid in
> the entire XML document.  I just want all items with the same @itemid
in
>  each of the itemlist element, how can I do that?

don't you just want to replace

<xsl:key name="items-by-itemid" match="item" use="@itemid"/>

by something like

<xsl:key name="items-by-itemid" match="item"
use="concat(generate-id(..),@itemid)"
/>

so that your key values are all specific to a given itemlist.

Not that I've tried it....

David

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