[Bug translator/11424] New: 'kprobe.function("foo") !' doesn't work like 'kernel.function("foo") !'

["dsmith at redhat dot com" <sourceware-bugzilla at sourceware dot org>]

Observe the following:

# stap -e 'probe kernel.function("foo") !, kernel.function("sys_read")
{printf("read\n"); exit()}'
read
# stap -e 'probe kernel.function("foo") ?, kernel.function("sys_read")
{printf("read\n"); exit()}'
read

Since function "foo" doesn't exist, '!' (optional and sufficient) and '?'
(optional) act exactly the same.

However:

# stap -e 'probe kprobe.function("foo") ?, kprobe.function("sys_read")
{printf("read\n"); exit()}'
read
# stap -e 'probe kprobe.function("foo") !, kprobe.function("sys_read")
{printf("read\n"); exit()}'
<ctrl-C>

In this last case, '!' seems to mark "foo" as sufficient, even if it doesn't exist.

-- 
           Summary: 'kprobe.function("foo") !'  doesn't work like
                    'kernel.function("foo") !'
           Product: systemtap
           Version: unspecified
            Status: NEW
          Severity: normal
          Priority: P2
         Component: translator
        AssignedTo: systemtap at sources dot redhat dot com
        ReportedBy: dsmith at redhat dot com


http://sourceware.org/bugzilla/show_bug.cgi?id=11424

------- You are receiving this mail because: -------
You are the assignee for the bug, or are watching the assignee.