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Re: ISO C99 support in <math.h> for C++98

On 2016-03-22 12:46, Andre Vieira (lists) wrote:
On 22/03/16 15:42, Yaakov Selkowitz wrote:
We also had issues enabling C99-in-C++ on Cygwin (which is based on
newlib), which required a few patches:

It is on my to-do list to get this working on newlib targets once we
have a snapshot with the new feature test macros.

Ok so I now know where the problem is coming from, its the fact that
_GLIBCXX98_USE_C99_MATH is defined based on the configure which uses
-std=g++98, whereas the test in libstdc++ uses -std=gnu++98. The first
ends up with a __ISO_C_VISIBLE 1990 the latter 1999 because
_POSIX_C_SOURCE is defined as 200809L for gnu++98 and undefined for c++98.

This was working before because the C99 functions would always be
included when compiling for c++ due to the || defined(__cplusplus),
adding this back would fix it, but I'm assuming you removed it for a
reason. I will look further into why this discrepancy in macros for
c++98 and gnu++98.

AFAICS the configure tests are incorrect here. C++98, which obviously predates C99, can not and should not rely upon nor expose the latter's features. The feature test macros *do* enable C99 and C11 when C++11 or newer is in effect.

Note that this is part of a larger issue, which affects glibc as well:

I do plan on working on this for newlib, and possibly even glibc, when I have a chance.


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