Re: fork call __attribute__((destructor))

[Yubin Ruan <ablacktshirt at gmail dot com>]

2017-08-05 15:02 GMT+08:00 Yubin Ruan <ablacktshirt@gmail.com>:
> 2017-08-05 2:10 GMT+08:00 Carlos O'Donell <carlos@redhat.com>:
>> On 08/04/2017 01:01 PM, Yubin Ruan wrote:
>>> Hi,
>>> I used to assumed that a function marked with a
>>> "__attribute__((destructor))" would be called after the .so is
>>> unloaded, typically when the program exit. However, I discover that
>>> when I call "fork()" the destructor is also called.
>>>
>>> How could that happen? Is it a bug or something? Am I doing something
>>> wrong? What is the rationale behind that?
>>>
>>> And, is there any way to prevent the destructor being called when
>>> somebody call fork()?
>>
>> Please provide an example program that does this.
>
> /* forklib.c, compile this to the .so file */
> __attribute__((destructor)) {
>     printf("Destructor is called\n");
> }
>
> /* main.c, use LD_PRELOAD=/path/to/the/xxx.so to tell the dynamic linker
>  * to load the .so file. You will see that the "destructor" is called
>  * after fork, in both parent and child
>  */
> #include <stdio.h>
> #include <unistd.h>
> int main()
> {
>     pid_t pid = fork();
>     if(0 == pid) {
>         printf("In child process\n");
>     }else{
>         printf("In parent process\n");
>     }
>     return 0;
> }
>

Sorry this example is wrong. I have proved that calling "fork()" won't
involve "__attribute__((destructor))"

Yubin