Re: parenthesis while addressing struct member

[JoÃl KrÃhemann <weedlight at gmail dot com>]

Carlos O'Donell wrote:
> On Sat, Jul 26, 2014 at 11:13 AM, JoÃl KrÃhemann <weedlight@gmail.com> wrote:
> > I experienced problems as not using parenthesis with addressing operator.
> > Does someone know what's correct?
> >
> > pthread_mutex_lock.c
> >
> >              int e = INTERNAL_SYSCALL (futex, __err, 4,
> > &mutex->__data.__lock,
> >          __lll_private_flag (FUTEX_LOCK_PI,
> > private), 1, 0);
> >
> > ags_thread-posix.c
> >
> >               pthread_mutex_init(&(thread->timelock_mutex), NULL);
> They are both the same.
>
> The -> and . have precedence over & with left-to-right associativity.
>
> Therefore &(struct->member) is equivalent to &struct->member.
>
> Only () can change this e.g. *(ptr[x]) is not equivalent (*ptr)[x].
>
> Cheers,
> Carlos.
Further I really believe it should rather be of form like:

&(mutex->__data.__lock)

is it still the same?