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Re: pthread_mutex_unlock potentially cause invalid access
2012/2/13 Atsushi Nemoto <anemo@mba.ocn.ne.jp>:
> On Sun, 12 Feb 2012 17:38:33 -0500, "Carlos O'Donell" <carlos@systemhalted.org> wrote:
>>> On point "A", the mutex is actually unlocked, so other threads can
>>> lock the mutex, unlock, destroy and free. ?If the mutex was destroyed
>>> and freed by other thread, reading '__kind' on point "B" is not valid.
>>
>> No valid conforming program has this behaviour.
> ...
>> If {X-X'} need to be prevented from using M then you need to use
>> *another* synchronization primitive, we call it P, to prevent the use
>> M during the destruction of M.
>
> How about following example in pthread_mutex_destroy manual?
> It seems it can be possible without P.
>
> http://pubs.opengroup.org/onlinepubs/007904875/functions/pthread_mutex_destroy.html
> ------------------------------------------------------------------------
> ? ?Destroying Mutexes
>
> ? ?A mutex can be destroyed immediately after it is unlocked. For
> ? ?example, consider the following code:
>
> ? ?struct obj {
> ? ?pthread_mutex_t om;
> ? ? ? ?int refcnt;
> ? ? ? ?...
> ? ?};
>
> ? ?obj_done(struct obj *op)
> ? ?{
> ? ? ? ?pthread_mutex_lock(&op->om);
> ? ? ? ?if (--op->refcnt == 0) {
> ? ? ? ? ? ?pthread_mutex_unlock(&op->om);
> ? ?(A) ? ? pthread_mutex_destroy(&op->om);
> ? ?(B) ? ? free(op);
> ? ? ? ?} else
> ? ?(C) ? ? pthread_mutex_unlock(&op->om);
> ? ?}
>
> ? ?In this case obj is reference counted and obj_done() is called
> ? ?whenever a reference to the object is dropped. Implementations are
> ? ?required to allow an object to be destroyed and freed and potentially
> ? ?unmapped (for example, lines A and B) immediately after the object is
> ? ?unlocked (line C).
> ------------------------------------------------------------------------
>
> In this example, (A) and (B) can be executed in middle of (C) execution.
> Thus, problem can be happen even on a fully conforming program, no?
Heh, Interesting. I think you are right.
At first, I thought we don't need to fix this likes Carlos because the
standard says
http://pubs.opengroup.org/onlinepubs/007904875/functions/pthread_mutex_destroy.html
pthread_mutex_destroy:
It shall be safe to destroy an initialized mutex that is unlocked.
Attempting to destroy a locked mutex results in undefined behavior.
So, while thread T is under mutex_unlock, any other thread shouldn't
call pthread_mutex_destroy(). Thus, current implementation fullfill a
requirement of the standard. But, yes, it also violate an example code
of the standard. iow, SUS is suck.
And, now lll_unlock has costly atomic operation (A) and syscall (B),
> #define lll_unlock(lock, private) \
> ((void) ({ \
> int *__futex = &(lock); \
> int __val = atomic_exchange_rel (__futex, 0); \ (A)
> if (__builtin_expect (__val > 1, 0)) \
> lll_futex_wake (__futex, 1, private); \ (B)
> }))
thus, a few register move are much less costly than that. Plus,
userland application developers hope non-x86 code works the same as
x86. so, I think your proposal has good benefit/cost ratio.