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How does GDB know the architecture of an executable?
- From: fei ding <fdingiit at gmail dot com>
- To: gdb at sourceware dot org
- Date: Fri, 16 Jan 2015 11:47:47 +0800
- Subject: How does GDB know the architecture of an executable?
- Authentication-results: sourceware.org; auth=none
Hi guys:
I'm wondering how does GDB know the architecture of an executable, for
example, if I use -m32 options in gcc and I can get an i386
executable, if I use nothing I'll get a x86-64 executable while I am
compiling code on a 64-bit Linux.
I've see the source code for one day but I cannot get what I want, at
first I think '''struct gdbarch''' has something with it. Can anyone
help me? I want to know everything about this.
Thanks a lot.