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Re: [PATCH 5/5] gdb: change print format of flag enums with value 0


On 2/13/20 5:30 PM, Simon Marchi wrote:
If a flag enum has value 0 and the enumeration type does not have an
enumerator with value 0, we currently print:

   $1 = (unknown: 0x0)

I don't like the display of "unknown" here, since for flags, 0 is a
an expected value.  It just means that no flags are set.  This patch
makes it so that we print it as a simple 0 in this situation:

Should we print "no flags set" alongside the 0 for this case then?


   $1 = 0

If there is an enumerator with value 0, it is still printed using that
enumerator, for example (from the test):

   $1 = FE_NONE

gdb/ChangeLog:

	* valprint.c (generic_val_print_enum_1): When printing a flag
	enum with value 0 and there is no enumerator with value 0, print
	just "0" instead of "(unknown: 0x0)".

gdb/testsuite/ChangeLog:

	* gdb.base/printcmds.exp (test_print_enums): Update expected
	output.
---
  gdb/testsuite/gdb.base/printcmds.exp |  2 +-
  gdb/valprint.c                       | 31 +++++++++++++++++++++-------
  2 files changed, 25 insertions(+), 8 deletions(-)

diff --git a/gdb/testsuite/gdb.base/printcmds.exp b/gdb/testsuite/gdb.base/printcmds.exp
index d6f5c75650bf..bd2afc8696f0 100644
--- a/gdb/testsuite/gdb.base/printcmds.exp
+++ b/gdb/testsuite/gdb.base/printcmds.exp
@@ -743,7 +743,7 @@ proc test_print_enums {} {
      gdb_test "print (enum flag_enum) 0x0" [string_to_regexp " = FE_NONE"]
# Print a flag enum with value 0, where no enumerator has value 0.
-    gdb_test "print flag_enum_without_zero" [string_to_regexp " = (unknown: 0x0)"]
+    gdb_test "print flag_enum_without_zero" [string_to_regexp " = 0"]
# Print a flag enum with unknown bits set.
      gdb_test "print (enum flag_enum) 0xf1" [string_to_regexp " = (FE_ONE | unknown: 0xf0)"]
diff --git a/gdb/valprint.c b/gdb/valprint.c
index bd21be69e1bf..6e62d420c0f4 100644
--- a/gdb/valprint.c
+++ b/gdb/valprint.c
@@ -634,7 +634,6 @@ generic_val_print_enum_1 (struct type *type, LONGEST val,
        /* We have a "flag" enum, so we try to decompose it into
  	 pieces as appropriate.  A flag enum has disjoint
  	 constants by definition.  */
-      fputs_filtered ("(", stream);
        for (i = 0; i < len; ++i)
  	{
  	  QUIT;
@@ -646,24 +645,42 @@ generic_val_print_enum_1 (struct type *type, LONGEST val,
if ((val & enumval) != 0)
  	    {
-	      if (!first)
+	      if (first)
+		{
+		  fputs_filtered ("(", stream);
+		  first = 0;
+		}
+	      else
  		fputs_filtered (" | ", stream);
-	      first = 0;
val &= ~TYPE_FIELD_ENUMVAL (type, i);
  	      fputs_filtered (TYPE_FIELD_NAME (type, i), stream);
  	    }
  	}
- if (first || val != 0)
+      if (val != 0)
  	{
-	  if (!first)
+	  /* There are leftover bits, print them.  */
+	  if (first)
+	    fputs_filtered ("(", stream);
+	  else
  	    fputs_filtered (" | ", stream);
+
  	  fputs_filtered ("unknown: 0x", stream);
  	  print_longest (stream, 'x', 0, val);
+	  fputs_filtered (")", stream);
+	}
+      else if (first)
+	{
+	  /* Nothing has been printed and the value is 0, the enum value must
+	     have been 0.  */
+	  fputs_filtered ("0", stream);
+	}
+      else
+	{
+	  /* Something has been printed, close the parenthesis.  */
+	  fputs_filtered (")", stream);
  	}
-
-      fputs_filtered (")", stream);
      }
    else
      print_longest (stream, 'd', 0, val);

Otherwise LGTM.


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