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Re: [PATCH] gdbserver gnu/linux: stepping over breakpoint
- From: Pedro Alves <palves at redhat dot com>
- To: Yao Qi <qiyaoltc at gmail dot com>
- Cc: gdb-patches at sourceware dot org
- Date: Thu, 09 Apr 2015 16:24:56 +0100
- Subject: Re: [PATCH] gdbserver gnu/linux: stepping over breakpoint
- Authentication-results: sourceware.org; auth=none
- References: <1428569112-18004-1-git-send-email-qiyaoltc at gmail dot com> <552645C2 dot 6080004 at redhat dot com> <86y4m1uysh dot fsf at gmail dot com> <55269925 dot 8090704 at redhat dot com>
On 04/09/2015 04:22 PM, Pedro Alves wrote:
> On 04/09/2015 04:06 PM, Yao Qi wrote:
>> Pedro Alves <palves@redhat.com> writes:
>>
>>> even reached. The test isn't even threaded. It sounds like
>>> gdbserver is trying to step over the breakpoint at "foo"? Didn't
>>> gdb itself step over it? How come that was reached in gdbserver?
>>> Did we mishandle the breakpoint's reference count in gdbserver?
>>
>> Shouldn't GDBserver step over breakpoint when the target side condition
>> is false?
>
> Oh, this is stepping past an hardware breakpoint, not software
> breakpoint. Yes, GDBserver should be stepping past such
> breakpoints. But, given GDBserver's software single-step
> support is really really really really too simple:
>
> /* We only place breakpoints in empty marker functions, and thread locking
> is outside of the function. So rather than importing software single-step,
> we can just run until exit. */
> static CORE_ADDR
> arm_reinsert_addr (void)
> {
> struct regcache *regcache = get_thread_regcache (current_thread, 1);
> unsigned long pc;
> collect_register_by_name (regcache, "lr", &pc);
> return pc;
> }
>
> ... we should probably disable target side conditions on software
> single-step gdbserver ports. E.g., try "si" through this function:
Sorry, "si" probably works as gdb steps over the breakpoint
itself. Try "step" or "next" instead, which kick in the range
stepping support, which then causes gdbserver to handle the
step-over itself.
>
> void
> function ()
> {
> i = 0;
> i = 0; // set cond breakpoint that evals false here
> i = 0;
> }
>
> I'd guess the "si" over the breakpoint ends in the caller
> of "function"...
Thanks,
Pedro Alves