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-x weirdness


When I installed cygwin, permissions on all the distribution looks like:

###############################################################################
$ ls -al /usr/bin/bash
-rwx------+   1 Administ Domain U   531968 Mar 13 04:29 /usr/bin/bash*
###############################################################################

As you can see, even if I am:

###############################################################################
$ id 
uid=17199(benoitr) gid=10513(Domain Users) groups=10513(Domain Users),11121(Exceed Users)
###############################################################################

I can however run bash and every other programs. I suppose
it is a Windoze weirdness. But, what is interesting is "How
can I know if a program can be executed"? Often, I write
scripts where the flow of control depend on the availability
of a particular program.

So check this out:

###############################################################################
$ [ -x /usr/bin/bash ]; echo $?
0
$ /usr/bin/test -x /usr/bin/bash; echo $?
1
$ perl -e 'print -x "/usr/bin/bash" ? 0 : 1 , "\n"'
1
###############################################################################

I guess only bash is correct...

Looking at the source code of bash (in test.c), we discover
what seems to be the "correct" way of guessing if a program
can be executed:

    case 'x':                   /* File is executable? */
      return (EACCESS (arg, X_OK) == 0);

where EACCESS is:

#if defined (AFS) || defined (__CYGWIN__)
#  define EACCESS(path, mode)   access(path, mode)
#else
#  define EACCESS(path, mode)   test_eaccess(path, mode)
#endif /* AFS */


I'd like to know if:

Someone will notice and eventually correct the bug

- or -

I'm wrong, this is not a bug

- or -

Tell me a way to interprete these results.

Do I have to mail this problem to a perl mailing list?

Thanks

-- 
           *º¤., ¸¸,.¤º*¨¨¨*¤  Benoit Rochefort  *º¤., ¸¸,.¤º*¨¨¨*¤


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