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Bash traps - while emitting ERR trap
- From: Andrew DeFaria <ADeFaria at Salira dot com>
- To: cygwin at cygwin dot com
- Date: Wed, 30 Jul 2003 12:15:07 -0700
- Subject: Bash traps - while emitting ERR trap
Given the following script:
#!/bin/bash
function cleanup { echo "ENTER cleanup"
} # cleanup
trap cleanup EXIT ERR
declare -i i=4 echo "Entering while loop"
while [ $i -gt 0 ]; do
echo "In while loop"
let i=i-1
done echo "After trap is set"
Why is "ENTER cleanup" echoed twice when run?
$ traptest
Entering while loop
In while loop
In while loop
In while loop
In while loop
ENTER cleanup
After trap is set
ENTER cleanup
If I remove the EXIT from the trap statement then I get the following
Entering while loop
In while loop
In while loop
In while loop
In while loop
ENTER cleanup
After trap is set
and if I omit the ERR from the trap statement I get the following:
Entering while loop
In while loop
In while loop
In while loop
In while loop
After trap is set
ENTER cleanup
It seems as though the EXIT trap is getting invoked properly when the
script exits but the ERR trap is being generated upon exit of the while
loop. Is this correct behavior? If is it correct behavior then how can I
script a cleanup routine to trap properly for such things as EXIT ERR
and INT in the presence of while loops?
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