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Re: DLL calling a DLL: undefined reference when linking.
"Elfyn McBratney" <elfyn-cygwin at exposure dot org dot uk> wrote in message
news:031a01c2dadb$bf7b0a40$666d86d9 at webdev dot dot dot
> > I think I'm making marvelous progress. Unfortunately, I'm getting
> > error that doesn't make sense:
> > $g++ -shared -mno-cygwin -o dllhello.dll dllhello.o
> > other.dll -Wl,--out-implib,libdllhello.a -Wl,--enable-stdcall-fixup
> > Creating library file: libdllhello.a
> > dllhello.o(.text+0x164):dllhello.C: undefined reference to `InitAPI at 4'
> > In my source code, the offending call is:
> > extern "C" PASCAL void InitAPI( int handle );
> Does dllhello.c include a header containing the prototype of InitAPI or
> a declaration of InitAPI? I think that's the gotcha.
> Elfyn McBratney
> elfyn at exposure dot org dot uk
Both the extern prototype and the function call are in dllhello.C. Thus it
does see the prototype. As a further note and after further testing, if I
use implib on other.dll, I get the export list. If I add an alias in the
InitAPI at 4
InitAPI=InitAPI at 4
then use dlltool to create the library, I can link against that library
So it seems clear that --enable-stdcall-fixup isn't working as advertised.
Any idea why?
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