Bug 12932

Created attachment 5820 [details]
Test case

*Tested on GDB 7.3.50.20110624 x86_64*

In the next code, add a breakpoint in the function `f' with
the command `break f'. The breakpoint is placed after the
last brace of `for (;;)' which is wrong. It makes bypass the
first iteration of the loop. When the breakpoint is hit then i=1:

=================================================
void f(char *s, int i)
{
        for (;;) {
                if (s[i++] == '\n')
                        break;
        } <--- breakpoint set here with `break f'
               with i=1
}

int main(int argc, char *argv[])
{
        char buf[] = "0123456789\n";

        f(buf, 0);

        return 0;
}
=================================================