Re: [xsl] Select a node by name

[Andreas Schlegel <schlegel at software dot b dot uunet dot de>]

Di Dion,

thanks for your help. It works fine :-)

Greetings,
Andreas


Dion Houston wrote:

> Hi Andreas:
>
> There's actually a couple issues here...
>
> The select issue is actually pretty easy and straight forward.  To
> select the person element who has a name attribute of Betty, simply use
> the XPath: 
> /persons/person[@name="Betty"]
>
> The second issue is that xsl:value-of outputs the text content of the
> node you specify.  So in the case of:
>
> <xsl:value-of select="/persons/person[@name='Betty']"/>
>
> This will actually display nothing.  Why?  In your sample XML below, the
> person _element_ has no text content.
>
> If what you're looking for is (for example) the job, then use the
> following:
>
> <xsl:value-of select="/persons/person[@name='Betty']/@job"/>
>
> HTH!
>
> Dion
> -----Original Message-----
> From: Andreas Schlegel [mailto:schlegel@software.b.uunet.de] 
> Sent: Friday, October 04, 2002 3:26 PM
> To: XSL-List@lists.mulberrytech.com
> Subject: [xsl] Select a node by name
>
> Hi,
>
> writing a XSL file I have the problem to get a specific node of the
> list.
>
> Having a XML file like this:
>
> <persons>
> <person name="Bill" job="Developer"/>
> <person name="Steve" job="Admin"/>
> <person name="Betty" job="CEO"/>
> </persons>
>
> A statement like <xsl:value-of select="person"/> won't help because I 
> have a lot of nodes of the type PERSON.
>
> If I have a node already selected I may use <xsl:value-of
> select="@name"/>
>
> It's no problem to do it by for each ( <xsl:for-each select="person"> ).
>
> But I look for a way to pick a person out of the list, i.e. "Betty".
>
> Any ideas?
>
> Greetings,
> Andreas
>
>
>
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>
>
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>
>  


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