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Re: Re: print out the actual node (NEWBIE)
- From: "G. Ken Holman" <gkholman at CraneSoftwrights dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Mon, 16 Sep 2002 15:55:20 +0200
- Subject: Re: [xsl] Re: print out the actual node (NEWBIE)
- References: <3D85A2DC.7040205@ksc.ch>
- Reply-to: xsl-list at lists dot mulberrytech dot com
Check out the SHOWTREE free resource in the resource library linked near
the top of our home page noted below ... this stylesheet exposes the entire
XPath node tree for an arbitrary XML document. The path down to a node is
maintained at each level of the tree. I'm not sure what your context is
for wanting to display the path, so I'm not sure if this is what you need.
I hope this helps.
................ Ken
At 2002-09-16 15:16 +0200, thomas wrote:
I found a resolution. ugly hack I think...but it works
<xsl:value-of select="name(../../../..)"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="name(../../..)"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="name(../..)"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="name(..)"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="name()"/>
thomas wrote:
Im having problems with my template and I think somehow its related to
the node. Is there a way to print out the actual node I'm in?
<a>
<b/>
<c>
<xsl:value-of select="name()"/>
</c>
<d/>
</a>
prints out only "c"
but I need "a/c"
cant find anything.
thanx
le beck
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