RE: [xsl] Hierarchy problem

[DPawson at rnib dot org dot uk]

> -----Original Message-----
> From: Jeni Tennison [mailto:jeni@jenitennison.com]
> Sent: 22 July 2002 10:54
> To: xsl-list@lists.mulberrytech.com
> Subject: Re: [xsl] Hierarchy problem
> 
> 
> Dave,
> 
> David C made a typo when he wrote:
> >> just if $y is a child of $x which is what I think you mean 
> by direct
> >> descendant.
> >> 
> >> count($x//*|$y) = count($x/*)
> >> 
> >> if $y is a descendent of $x
> 
> He meant:
> 
>   count($x//*|$y) = count($x//*)
>                              ^ additional /

That's it.


 <level1 id='l1'>
   <h1>Level1</h1>
   <level2 id='l2'>
    <h2>Level2</h2>  <!-- bad navPoint 1 -->
    <level3 id='l3'> <!-- good navPoint 2 -->
     <h3>level3</h3>
     <note id="noteId">  <!-- navLabel target -->
      <p>Note content</p>
     </note>
    </level3>
   </level2>
  </level1>

<xsl:variable name='x' select='/level1/level2/level3/note'/>
<xsl:variable name='y' select='/level1'/>


<xsl:template match="/">
  <xsl:message>Y is a desc of X:<xsl:value-of 
  select="count($x//*|$y) = count($x/*)"/></xsl:message>

  <xsl:message>X is a desc of Y:<xsl:value-of 
  select="count($y//*|$x) = count($y//*)"/></xsl:message>
 

</xsl:template>

Gives:
Y is a desc of X:false
X is a desc of Y:true



In this case note is a descendent of level1, so $x should be a descendent of
$Y.

This goes back to the idea of the union ignoring duplicates (count only
once)?
hence 

count($x//*|$y) = count($x//*)

implies that node $y is a member of the set which is all the children of $x?

Is that right?


Still doesn't resolve my original problem though.
the hierarchy above is
 level1
   level2
    level3
I'm looking for *immediate* descendent, i.e. level3 (and hence note)
are not *immediate* descendents of level1, level2 intervenes.

I'm playing with Dimitres suggestion, along the lines of

var myNearestParentLevel = substring-after(ancestor-or-self(contains
(name('level')) ...
  i.e. get '3' for note as being the nearest wrapper.

then use Dimitres ideas to check if (for level1) l+1 = $myNearestParentLevel

 which is false.

Regards DaveP



regards DaveP




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