This is the mail archive of the
xsl-list@mulberrytech.com
mailing list .
Re: Testing for presence of node
- From: "Dhruvraj Singh" <sdhruv at aalayance dot com>
- To: <xsl-list at lists dot mulberrytech dot com>, "TheList" <thelist at lists dot evolt dot org>
- Date: Fri, 21 Jun 2002 19:35:16 +0530
- Subject: Re: [xsl] Testing for presence of node
- References: <PEEOKEDDEBLLMOCJBGMDCEGGCFAA.jjk3@msstate.edu>
- Reply-to: xsl-list at lists dot mulberrytech dot com
For each category element if you want to check for
subcategory as its children, you can do :
<xsl:for-each select="//category">
<xsl:if test="string-length(./*[name()=subcategory]) >0 )
Success
</xsl:if>
<xsl:if test="string-length(./*[name()=subcategory])=0 )
Failure
</xsl:if>
</xsl:for-each>
>
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> I have an XML file that contains the following structure:
>
> <category>
> <subcategory>
> <article>
> </article>
> </subcategory>
> </category>
>
> In my XSLT stylesheet, I need to be able to test if the <category>
> node I'm working with contains a <subcategory> node. What's the best
> way to test for the presence of this node without actually doing
> anything with it? I was thinking <xsl:if test="something">.
>
> - -joeljkp
>
> - ---------------------------------------
> http://www.ballsome.com
>
> -----BEGIN PGP SIGNATURE-----
> Version: PGPfreeware 7.0.3 for non-commercial use <http://www.pgp.com>
>
> iQA/AwUBPRKA7H880CLOJa2eEQJxpwCg6XhYuz/DsUThGatqbkDa99G85XAAoL8b
> GrkEiFZTOBoCy9EHV1HxOiTA
> =ASvZ
> -----END PGP SIGNATURE-----
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list