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Re: Transformation in NetScape 6.2 Browser
- From: "Roma Yankin" <polfin at narod dot ru>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Wed, 8 May 2002 23:58:31 +0400
- Subject: Re: [xsl] Transformation in NetScape 6.2 Browser
- References: <000a01c1f610$5d5efb60$ebd0690a@tibco.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi Pundalik,
Actually there is no difference in transforming xml documents both for IE6
and NS6. However you might be using transformNode() method from JS which is
implemented only in IEs with MSXML 3 and higher installed.
Anyway check out this code that makes simplest trasformation of an xml tree.
XML file:
~~~~~~~~~~~~~~~~~~~~~~~~~~~
<?xml-stylesheet type="text/xsl" href="xsl.xsl"?>
<sample>
<hasattrib hasit="true">
I have attribute
</hasattrib>
<ihave hasit="candy">
I have attribute
</ihave>
<noattribute>
Nothing here
</noattribute>
<mychildhave>
<child hasit="toy"/>
</mychildhave>
</sample>
XSL file:
~~~~~~~~~~~~~~~~~~~~~~~~~~~
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="html"/>
<xsl:template match="/">
<html>
<body>
<xsl:for-each select=".//*">
<xsl:if test="@hasit">
<b><xsl:value-of select="name()"/></b> have "hasit" attribute set to
<b><xsl:value-of select="@hasit"/></b> <br/>
</xsl:if>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
This will work both in IE and NS,
----
regards Roman!
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