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RE: xsl:copy
- From: Jarno dot Elovirta at nokia dot com
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Tue, 19 Feb 2002 08:23:39 +0200
- Subject: RE: [xsl] xsl:copy
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi
> I need to generate a copy of an xml file using xsl ...I tried using
> xsl:copy..but this gives me only the value and not the node
> names ....Is
> there a workaround to accomplish this.
With xsl:copy, this would to it
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
but it's easier with xsl:copy-of, i.e.
<xsl:template match="/">
<xsl:copy-of select=".">
</xsl:template>
Santtu
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