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Re: outputting an <a href> with a URL which contains "&func"
- From: "Joerg Heinicke" <joerg dot heinicke at gmx dot de>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Mon, 21 Jan 2002 23:56:46 +0100
- Subject: Re: [xsl] outputting an <a href> with a URL which contains "&func"
- References: <Pine.OSF.4.33.0201211727370.4390-100000@csgrad.cs.vt.edu>
- Reply-to: xsl-list at lists dot mulberrytech dot com
In XML you have to replace & by & and < by < . Then you don't need
these constructs with disable-output-escaping (avoid this in general!!) and
CDATA.
Regards,
Joerg
----- Original Message -----
From: "Saverio Perugini" <sperugin@csgrad.cs.vt.edu>
To: <xsl-list@lists.mulberrytech.com>
Sent: Monday, January 21, 2002 11:36 PM
Subject: [xsl] outputting an <a href> with a URL which contains "&func"
> Hello,
>
> I'm trying to output an <a href> from an XSL template.
> The value of the href attribute is a URL which contains the string
> ``&func''
>
> The following results in an error regarding the reference to entity
"func".
> The error states that the reference must end with the ';' delimiter.
>
> <a><xsl:attribute name="href"><xsl:text
disable-output-escaping="yes">http://....?dtype=C&func=front&state=&style=">
</xsl:text></xsl:attribute></a>
>
> I have been able to circumvent this error with the following code.
>
> <a><xsl:attribute name="href"><xsl:text
disable-output-escaping="yes"><![CDATA[http://....?dtype=C&func=front&state=
&style=]]></xsl:text></xsl:attribute>
>
> Is this the correct method to achieve my desired result?
>
> Thank You,
>
> Saverio Perugini
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
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