Re: [xsl]How can I choose to ouput different nodeElement....

["G. Ken Holman" <gkholman at CraneSoftwrights dot com>]

At 2001-12-29 15:39 +0800, dragonjia wrote:
>there is something wrong with my XSL:

Since an XSLT stylesheet is an XML document, it must be well formed.

It helps when writing stylesheets to think of elements and attributes as 
nodes of a node tree and not angle brackets of markup.

Also, you have assigned non-IDable name tokens to your attributes named ID 
(though I see that without the DTD they aren't typed ID).  You could just 
take advantage of the position of the media child ... but that is another 
question.

>I know I can repeat the whole paragraph  in both  when  and otherwise 
>container.

Or you could assign the table line to a variable and put the variable 
contents in each:

<xsl:variable name="contents">
<td>
<xsl:value-of select="@id"/>
</td>
<td align="center">
<xsl:value-of select="."/>
</td>
<td align="center">
<xsl:value-of select="@num"/>
</td>
</xsl:variable>
...
<xsl:choose>
<xsl:when test="(@id mod 2)=0" >
         <tr bgcolor="#ffffcc">
<xsl:copy-of select="$contents"/>
        </tr>
</xsl:when>
<xsl:otherwise>
         <tr>
<xsl:copy-of select="$contents"/>
        </tr>
</xsl:otherwise>
</xsl:choose>

Then again, you could just decide on the background colour at the point in 
time, and not bother with the variable:

<tr>
<xsl:if test="(@id mod 2)=0">
   <xsl:attribute name="bgcolor">#ffffcc</xsl:attribute>
</xsl:if
<td>
<xsl:value-of select="@id"/>
</td>
<td align="center">
<xsl:value-of select="."/>
</td>
<td align="center">
<xsl:value-of select="@num"/>
</td>
</tr>

Depending on what other needs you may have, one of the two above may be 
better than the other.

I hope this helps.

............................... Ken



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