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RE: for-each order
- From: "Michael Kay" <michael dot h dot kay at ntlworld dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Fri, 14 Dec 2001 17:34:14 -0000
- Subject: RE: [xsl] for-each order
- Reply-to: xsl-list at lists dot mulberrytech dot com
>
> Hello,
> Is there a way to do <xsl:for-each ..... and looping backwards.
As it happens, there is.
<xsl:sort select="position()" data-type="number" order="descending"/>
It's actually a good conformance test for your processor!
Mike Kay
>
> My XML looks like
> <histo>
> <bar value="60" legend="Jan" />
> <bar value="77" legend="Feb" />
> <bar value="53" legend="Mar" />
> <bar value="14" legend="Apr" />
> </histo>
>
> and I want to store 14,53,77,60 in a variable .
>
>
> <xsl:variable name="position">
> <xsl:for-each select="$path">
> <xsl:value-of select="@value"/>,
> </xsl:for-each>
> </xsl:variable>
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list