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RE: sorting problem
- To: xsl-list at lists dot mulberrytech dot com
- Subject: RE: [xsl] sorting problem
- From: DPawson at rnib dot org dot uk
- Date: Thu, 25 Oct 2001 14:38:52 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
> I don't understand the question.
>
>
> After this:
>
> <xsl:for-each select="r">
>
> you are only hgoing to get each r element once.
There are 12800 r elements.
>
> so what is "a" here and why does it appear twice?
is the contents of the <termX> element.
I eventually resolved it with
<xsl:sort select="m655/*[last()]"/>
which I was quite surprised to find worked!
The functionality is to sort by bubbling up lower numbers,
giving a level sort which might be depicted as
term10 term4 term3
term 9 term8 term7
term 3 term 2
This would be the case for successive part records of
<r>
..
<m655>
<tag>
<term1>
...
<term10>
<r>
..
<m655>
<tag>
...
<term3>
<term4>
etc.
I.e. it sorted on the last one, irrespective of what 'number'
was present for X in termX.
I'm nearly there, just need to find out how to do it for
lower level groupings.
Regards DaveP
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