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Re: Position of a Child
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] Position of a Child
- From: Wendell Piez <wapiez at mulberrytech dot com>
- Date: Thu, 20 Sep 2001 14:58:24 -0400
- Reply-To: xsl-list at lists dot mulberrytech dot com
Frank,
What you mean by "position of that child inside the context node" is
actually a bit problematic, possibly meaning any of a number of things. How
to get it depends both on what you mean, and what your input data looks like.
For starters, you could try
(count(*[name()=$NodeName]/preceding-sibling::*) + 1) -- that is, 1 + the
number of the node's preceding element siblings. If you have mixed content
(and thus the siblings you want to count include text nodes), or if there's
some other wrinkle (such as more than one child node being named
$NodeName), come back.
position() isn't very useful because it returns the position of the context
node within the current node list, which isn't what you want. You could
make it be what you want by doing something like:
<xsl:for-each select="*">
<xsl:if test="name()=$NodeName">
<xsl:value-of select="."/>
<xsl:value-of select="position()"/>
</xsl:if>
</xsl:for-each>
But again, I'm making assumptions about what you really want -- and you can
see this is more roundabout than simple counting the preceding siblings.
Cheers,
Wendell
At 02:17 PM 9/20/01, you wrote:
>I'm having problems getting the child's position() of the context node.
>I reference the child by its name (stored in a variable), like this:
>
><xsl:value-of select="*[name()=$NodeName]"/>
>
>What I would like to get is the position of that child inside the context
>node.
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Wendell Piez mailto:wapiez@mulberrytech.com
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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