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Position of a Child
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Subject: [xsl] Position of a Child
- From: "Casadome, Francisco Javier" <Francisco dot Casadome at bowneglobal dot es>
- Date: Thu, 20 Sep 2001 20:17:43 +0200
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi all,
I'm having problems getting the child's position() of the context node.
I reference the child by its name (stored in a variable), like this:
<xsl:value-of select="*[name()=$NodeName]"/>
What I would like to get is the position of that child inside the context
node.
I don't seem to find the correct syntax for this.
Thanks in advance,
Frank.
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