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RE: how do I pass two xml document into a xsl in java
- To: xsl-list at lists dot mulberrytech dot com
- Subject: RE: [xsl] how do I pass two xml document into a xsl in java
- From: john dot li at ps dot ge dot com
- Date: Wed, 19 Sep 2001 14:27:27 -0400
- Reply-To: xsl-list at lists dot mulberrytech dot com
Thanks, I understand it and think it will work
only downside is it requires hard coding the global variable in xsl file
which I don't really want to.
John
-----Original Message-----
From: Michael Kay [mailto:mhkay@iclway.co.uk]
Sent: Tuesday, September 18, 2001 5:13 PM
To: xsl-list@lists.mulberrytech.com
Subject: RE: [xsl] how do I pass two xml document into a xsl in java
With most processors you can pass a document as the value of a stylesheet
parameter, though I don't think this is defined in JAXP.
What you can do, though, is to make your calling application implement the
URIResolver interface; nominate this class as your URIResolver; in your
stylesheet have a global variable
<xsl:variable name="doc2" select="document('my:doc2')"/>
and in your resolve() method, return the relevant Source object if the
requested URI is "my:doc2", (and return null otherwise).
Mike Kay
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of
> john.li@ps.ge.com
> Sent: 18 September 2001 22:00
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] how do I pass two xml document into a xsl in java
>
>
> Hi, xsl and java gurus,
>
> I use javax.xml.transform.Transformer.transform method to
> transform one xml
> file, now my xsl file needs to transform two xml files. The
> problem is the
> transform method takes only one Source object only. I don't
> want to have to
> save the java xml document to files and have the xsl file to
> read from the
> files because it will slow down the app.
>
> Any solution to how I can specify two xml documents and
> transform them in
> xsl? and how would xsl refer to these two different sources?
>
> Thanks
> John
>
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>
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