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RE: newbie qtn: best way to display a specific range of records (say, 5-10, or whatever)


Clark,
You haven't shown us the xml so this can probably be greatly improved
but try something like
<xsl:for-each select="//data/job[(position() &gt; //params/startrecord)
and position() &lt; //params/numrecords + //params/startrecord]">
...
Beginners rule number 2: Never use "//"

Ciao Chris

XML/XSL Portal
http://www.bayes.co.uk/xml


> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com 
> [mailto:owner-xsl-list@lists.mulberrytech.com] On Behalf Of 
> Clark Freifeld
> Sent: 19 September 2001 20:51
> To: XSL-List@lists.mulberrytech.com
> Subject: [xsl] newbie qtn: best way to display a specific 
> range of records (say, 5-10, or whatever)
> 
> 
> Hello all. I have just subscribed to the list, I am a newbie 
> to XSL. My 
> question is as follows:
> 
> Ideally what I want to do is something like this:
> 
> <xsl:for-each select="//data/job" startwith="//params/startrecord" 
> numrecords="//params/numrecords">
>   A 'job' in turn contains a few levels of data, display it 
> here in various 
> ways, no problem.
> </xsl:for-each>
> 
> So you see what I want: just a specific range of records, 
> based on integer 
> parameters supplied in the xml document itself. Preferably 
> I'd like to avoid 
> the method of iterating over all records, and simply not 
> displaying those 
> outside the range.
> 
> I'm sure this is something brutally obvious to the skilled 
> XSL user, but I 
> couldn't seem to find a clear way to do in the documentation 
> I looked at.
> 
> Thanks!
> 
> Clark
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 


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