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RE: Getting the latest date


Since your dates are suitable for lexicographical ordering,
how about the following (almost literally copied from
http://www.dpawson.co.uk/xsl/sect2/N6461.html#d194e703):

<xsl:template match="/">
    <xsl:variable name="maximum">
        <xsl:for-each select="//revision">
            <xsl:sort select="@date" order="descending" />
            <xsl:if test="position() = 1">
                <xsl:value-of select="."/>
            </xsl:if>
        </xsl:for-each>
    </xsl:variable>
    <html>
    <body>
        <xsl:value-of select="$maximum"/>
    </body>
    </html>
</xsl:template>


Greetings,
bas.alberts@group2000.nl



-----Original Message-----
From: Gustaf Liljegren [mailto:gustaf.liljegren@xml.se]
Sent: Wednesday, September 12, 2001 13:46
To: XSL List
Subject: [xsl] Getting the latest date


In a DTD I collect meta information about a document's history, like this:

<revision date="2000-04-19">1.0A</revision>
<revision date="2000-04-20">1.0B</revision>
<revision date="2000-04-21">1.0C</revision>

I need a way to pick out the latest date from these. The latest revision is
usually put on top of the others, but this may not always be the case. I
have considered converting the string "2000-04-19" to the number "20000419"
and then using the ceiling() function to get the latest date, but I'm
looking for a less complicated way of doing this.

Regards,

Gustaf Liljegren



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