[xsl] using position() with XPath

[Michael Sobczak <msobczak at yahoo dot com>]

Hi,

I need to use position() to get the position of
an ancestor to the current <childMenu> node. 
Using the following xml:

<?xml version="1.0" encoding="UTF-8"?>
<menus>
	<parentMenu type="upper" title="Main Menu">
		<childMenus>
			<childMenu title="News"/>
			<childMenu title="Discussions"/>
		</childMenus>
	</parentMenu>
	<parentMenu type="lower" title="International
Menu">
		<childMenus>
			<childMenu title="Distribution"/>
			<childMenu title="World Headquarters"/>
		</childMenus>
	</parentMenu>
</menus>

I created the the following template for the
<childMenu> node:

<xsl:template match="childMenu[@title]">
	<LI><xsl:value-of
select="position(ancestor::parentMenu)"/>_<xsl:value-of
select="position()"/>. <xsl:value-of
select="@title"/></LI>
	<xsl:apply-templates/>
</xsl:template>

However, both of the position() calls return the
same value, like so:

1. Main Menu 
1_1. News 
2_2. Discussions 

2. International Menu 
1_1. Distribution 
2_2. World Headquarters 

When I change the first value-of in the template
to use "1 +
count(parent::*/preceding-sibling::*)" as
described in the FAQs, I get this:

1. Main Menu 
1_1. News 
1_2. Discussions 

2. International Menu 
1_1. Distribution 
1_2. World Headquarters 

What do I need to do to determine the position of
the current node's ancestor?


Thank you for your help,

- Mike.

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