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Re: passing parameters to an import file
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: Re: [xsl] passing parameters to an import file
- From: "cutlass" <cutlass at secure0 dot com>
- Date: Mon, 10 Sep 2001 12:19:18 +0100
- References: <EBEKJPOMOCIKIIPPEBHBOEEOCFAA.tmohammad@entier-solutions.com>
- Reply-To: xsl-list at lists dot mulberrytech dot com
try using the with-param
<xsl:call-template name="">
<xsl:with-param name="" select=""/>
</xsl:call-template>
though i suspect this may not be supported across all parsers with
document() calls, and not quite sure if it is supported at all, will be
interesting to know though.
cheers, jim fuller
----- Original Message -----
From: "Tanzila Mohammad" <tmohammad@entier-solutions.com>
To: <xsl-list@lists.mulberrytech.com>
Sent: Monday, September 10, 2001 12:18 PM
Subject: [xsl] passing parameters to an import file
> I have a xsl stylesheet (main.xsl) which imports another xsl stylesheet
> (common.xsl).
>
> Within main.xsl there is the following code:
>
> <xsl:call-template name="noResults"/> <!--noResults is contained within
the
> common.xsl-->
>
> However, common.xsl requires a parameter which is utilized by the
noResults
> template, is there a way to pass the parameter to the template from
main.xsl
> via the call?
>
> Something like this:
>
> <xsl:call-template name="noResults(<xsl:value-of select="$param"/>)"/>
>
> Thanks
>
> Tanzila
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
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