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Accessing URL Parameters In A XSLT Page
- To: XSL-List at lists dot mulberrytech dot com
- Subject: [xsl] Accessing URL Parameters In A XSLT Page
- From: "Haeko Pierce" <haeko at hotmail dot com>
- Date: Fri, 07 Sep 2001 13:06:37 -0700
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hello folks,
I'm having problems using xslt to access the parameters sent in a URL. This
is the URL that calls the my customer login xslt page, in this page I wanted
to read some parameters from the calling URL add a name parameter and
forward it to another page... This is how it goes
http://localhost/reservation/custlogin.xslt?AId=2&FId=3
This is my custlogin.xslt code
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" media="Mozilla"
href="ticketreservHTML.xsl"?>
<index xmlns:xslt="urn:oracle-xsql">
<topTitle>
Login Screen
</topTitle>
<pageTitle>Ticket Master</pageTitle>
<form action="/ticket/ticketresv.xsql" method="get">
<field name="AId" type="hiddenField">
<value>{@AId}</value>
</field>
<field name="Name" type="textField" case="U">
<Prompt>Your Name</Prompt>
</field>
<sendRequest type="button" label="Sign in"/>
</form>
</index>
Now in my xsl stylesheet, element <field name="AId"...> is mapped to HTML
tag <input type="hidden" name=AId value=..(i/p from url)>
I hoped to have the value for "AId" from the URL assigned to the "value"
attribute, so that I could pass them all into the page specified by the form
action attribute.
But the "value field" is empty and not getting populated with the values
from the URL.
Can someone please assist and tell me how to pass the url params to the next
page. Thanks for your time...
Cheers
Haeko
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