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RE: XPath Question
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] XPath Question
- From: "WATKIN-JONES,ADAM (HP-UnitedKingdom,ex1)" <adam_watkin-jones at hp dot com>
- Date: Fri, 7 Sep 2001 10:18:58 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
That works great!
I failed to appreciate the capabilities of '='. Having ready the
EqualityExpr section of your XSLT Programmer's reference I think I now
understand.
Thanks for the books, Saxon and for answering dumb questions from beginners
on the list!
> > Suppose I have this XML:
> >
> > <nodes>
> > <node id="1" parent="0"/>
> > <node id="2" parent="1"/>
> > <node id="3" parent="2"/>
> > </nodes>
> >
> > So, node 2 is the child of node 1, node 3 is the child of node 2.
> >
> > If I want to find the children of node 1 I believe I would write:
> > /nodes/node[@parent='1']
> >
> > But how do I write an XPath to select all the nodes that are
> > grandchildren
> > of node 1?
> >
> /nodes/node[@parent = /nodes/node[@parent='1']/@id]
>
> Mike Kay
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list