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Generating namespace declarations in output documents: How?
- To: XSL-List at lists dot mulberrytech dot com
- Subject: [xsl] Generating namespace declarations in output documents: How?
- From: David Moles <david dot moles at vykor dot com>
- Date: Wed, 05 Sep 2001 16:38:46 -0700
- Reply-To: xsl-list at lists dot mulberrytech dot com
So I've got this document more or less of the form
<foo>
...some elements...
</foo>
and I need to transform it into
<bar xmlns:xsi="http://www.w3.org/2000/10/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="[somewhere]">
...some elements...
</bar>
(yes, the transformation from foo to bar is pretty trivial at
the moment, but it's expected to get nastier later).
Of course the first thing I tried (since this is the first time
I've used XSL) is exactly what they tell you not to do in
section 7.1.3 of the XSLT spec --
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="foo">
<xsl:element name="bar">
<xsl:attribute name="xmlns:xsi">
http://www.w3.org/2000/10/XMLSchema-instance
</xsl:attribute>
<xsl:attribute name="xsi:noNamespaceSchemaLocation">
[somewhere]
</xsl:attribute>
<xsl:apply-templates/>
</xsl:template>
...some templates...
</xsl:transform>
-- you know, the part where it says "Thus, while it is not an error
to do [what I just did], it will not result in a namespace declaration
being output."
So what *will* result in a namespace declaration being output?
I read the FAQ at
http://www.dpawson.co.uk/xsl/sect2/N5536.html#d162e1308
but I confess that (1) I don't understand it, (2), it looks like
overkill, and (3), I have to think that anything involving
<xsl:text disable-output-escaping="yes">
has got to be The Wrong Thing for something as simple as what I'm
trying to do. The couple of FAQs below it don't look like what I
want either, or else the explanations aren't clear enough.
What am I missing?
Thanks,
David
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